How do you solve $x^2 - 20x + 100 = 36$ ?

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Answer 1 · 2018-03-24T17:34:55

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We have, $x^2-20x +100-36=0$

Or, $x^2-20x +64=0$

Carrying out middle-term factorization,we get,

$x^2-16x-4x +64=0$

$x(x-16)-4(x-16)=0$

$(x-16)(x-4)=0$

Thus,the two solutions of $x$ which we get are $x=16,4$

How do you solve x^2 - 20x + 100 = 36x^2 - 20x + 100 = 36?