What is the equation of the line with slope $m = - \frac{1}{2}$ $m= -1/2$ that passes through $(5, 3)$ $(5,3)$ ?

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What is the equation of the line with slope $m = - \frac{1}{2}$ $m= -1/2$ that passes through $(5, 3)$ $(5,3)$ ?

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Answer 1 · 2018-03-24T21:38:22

The equation of the line is $y = - \frac{1}{2} x + \frac{11}{2}$ $y=-1/2x+11/2$

Explanation:

As you know, equation of a line can be presented by y=mx+c (slope-intercept form). our slope (m)= $- \frac{1}{2}$ $-1/2$ so we will have to find c (the y-intercept). The rest is shown above.

$y = 3$ $y=3$ , $x = 5$ $x=5$ and $m = - \frac{1}{2} \to$ $m=-1/2 rarr$ We then substitute what we were given into our equation:

$3 = (- \frac{1}{2}) \cdot 5 + c \to$ $3=(-1/2)*5+c rarr$ We work out what we have

$3 = (- \frac{5}{2}) + c \to$ $3=(-5/2)+c rarr$ Add $(- \frac{5}{2})$ $(-5/2)$ to both sides which gives us $c = \frac{11}{2}$ $c=11/2$ , therefore equation of the line is $y = - \frac{1}{2} x + \frac{11}{2}$ $y=-1/2x+11/2$

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What is the equation of the line with slope $m = - \frac{1}{2}$ $m= -1/2$ that passes through $(5, 3)$ $(5,3)$ ?

1 Answer

Explanation:

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What is the equation of the line with slope $m = - \frac{1}{2}$ $m= -1/2$ that passes through $(5, 3)$ $(5,3)$ ?