What are the components of the vector between the origin and the polar coordinate (6, pi/3)?

1 Answer
Mar 25, 2018

(3,3sqrt(3))

Explanation:

The coordinates of the vector are the rectangular coordinates.

So let's convert the polar coordinates to rectangular form using the formula:

(r, theta)->(x,y)

x=rcostheta
y=rsintheta

x=(6)cos(pi/3)=6(1/2)=3

y=(6)sin(pi/3)=6(sqrt(3)/2)=3sqrt(3)

So the vector components are (3, 3sqrt(3))