If the length of fred's piece of paper is represented by 2x-6 ad the width is represented by 3x-5, then what is the perimeter and area of fred's paper?

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Answer 1 · 2018-03-26T02:03:35

Area #=6x^2-28x+30#

Perimeter #=10x-22#

So to start off, the perimeter is

#P = 2l+2w#

Then you input the width for #w# and the length for #l#. You get

#P = 2(2x-6) + 2(3x - 5)#

#P = 4x - 12 + 6x - 10#

#P = 10x - 22#

for the perimeter. For the area, you multiply.

#A=L*W #

So

#A = (2x-6)(3x-5)#

# = 6x^2-10x-18x+30#

#= 6x^2-28x+30#