How do you solve $2 (5 - x) - (- 2) (x - 3) = - (3 x - 4)$ $2(5-x)-(-2)(x-3) = -(3x-4)$ ?

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Answer 1 · 2018-03-27T17:32:28

$x = 0$ $x=0$

First, you need to expand all, which will give you

$10 - 2 x - (- 2 x + 6) = - 3 x + 4$ $10-2x-(-2x+6)=-3x+4$

$10 - 2 x + 2 x - 6 = - 3 x + 4$ $10-2x+2x-6=-3x+4$

Collect all the unknowns on the left side

$3 x = 4 - 4$ $3x=4-4$

$x = 0$ $x=0$

How do you solve 2(5−x)−(−2)(x−3)=−(3x−4)2(5-x)-(-2)(x-3) = -(3x-4)?