How do you solve $- 2 | 7 - 3 y | - 6 = 14$ $-2abs(7 - 3y) - 6 = 14$ ?

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How do you solve $- 2 | 7 - 3 y | - 6 = 14$ $-2abs(7 - 3y) - 6 = 14$ ?

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Answer 1 · 2018-03-29T12:55:28

This Equation have not solution:

Explanation:

$- 2 | 7 - 3 y | - 6 = 14$ $-2 abs(7-3y)-6=14$
$- 2 | 7 - 3 y | = 14 + 6$ $-2 abs(7-3y)=14+6$
$- 2 | 7 - 3 y | = 20$ $-2 |7-3y|=20$
$| 7 - 3 y | = \frac{20}{- 2}$ $|7-3y|=20/(-2)$
$| 7 - 3 y | = - 10$ $|7-3y|=-10$
And Absolut value is positive ever, then is impossible that value: -10

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How do you solve $- 2 | 7 - 3 y | - 6 = 14$ $-2abs(7 - 3y) - 6 = 14$ ?

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Explanation:

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How do you solve −2|7−3y|−6=14-2abs(7 - 3y) - 6 = 14?

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Explanation:

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How do you solve $- 2 | 7 - 3 y | - 6 = 14$ $-2abs(7 - 3y) - 6 = 14$ ?