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Given the function #f(r)=sqrt(r+1)-5#, what is f(-1)?

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1 Answer

Mar 29, 2018

#f(-1)=-5#

Explanation:

#f(r)=sqrt(r+1)#

#f(-1) = sqrt(-1+1)-5#

#f(-1)=sqrt0-5#

#f(-1)=0-5#

#f(-1)=-5#

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