How do you solve #7y + 2( y - 2) = 6( y + 1) - 3#?

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Answer 1 · 2018-04-04T11:45:32

#y=3#

#7y+2*(y-2)=6*(y+1)-3#

#7y+2y-6=6y+6-3#

#9y-6=6y+3#

#3y=9#

#y=3#

Answer 2 · 2018-04-04T11:46:38

Put all the y on one side of the equation, all numbers on the other.

#7*y+2*(y−2)=6*(y+1)−3#

Multiply the parenthesis.

#7*y+2*y+2*(-2)=6*y+6-3#
#7*y+2*y-4=6*y+6-3#
#9*y-4=6*y+3#

Subtract 6y, and add 4.

#9*y-6*y-4+4=6*y-6*y+3+4#
#9*y-6*y=3+4#
#3*y=7#

Divide with 3.

#y=7/3#