Question

How do you solve `6t ^ { 2} = - 4t`?

Answer 1

`t=0 or t=-2/3`

Explanation:

`6t^2+4t=0`

`2t(3t+2)`=0

`2t=0 or 3t=-2`

`t=0 or-2/3`

Answer 2

`t=0` and `t=-2/3`

Explanation:

Add `-4t` to both sides:

`6t^2+4t=cancel(-4t+4t)`

`6t^2+4t=0`

We can then factor out `2t`:

`2t(3t+2)=0`

We can then use the zero factor principle to know that this equation holds either when `2t=0` or when `3t+2=0`. This gives us two different solutions:

`2t=0->t=0`

`3t+2=0->-2/3`

These are the solutions to the equation.

Answer 3

The answer is : -2/3

Explanation:

Hello there!!

Let me explain how to do this.....
It is very simple.

Take,

`6t^2 = -4t`

Now " t " is cancelled out on both sides,

`6t = -4`

then,
`t = -4 / 6`

Now your answer is ready that is:

`t = -2/3` or `t = 0`

Hope you like my answer.......