How do you solve $3 + 4 (z + 5) = 31$ $3+4(z+5)=31$ ?

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How do you solve $3 + 4 (z + 5) = 31$ $3+4(z+5)=31$ ?

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Answer 1 · 2018-04-08T07:11:27

see below

Explanation:

We have, $3 + 4 (z + 5) = 31$ $3+4(z+5)=31$
Or, $3 + 20 + 4 z = 31$ $3+20+4z=31$
or, $4 z = 31 - 23$ $4z=31-23$
$z = 8 / 4$ $z=8//4$
Thus, $z$ $z$ comes out to be $2$ $2$ .

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How do you solve $3 + 4 (z + 5) = 31$ $3+4(z+5)=31$ ?

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How do you solve 3+4(z+5)=313+4(z+5)=313+4(z+5)=31?

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How do you solve $3 + 4 (z + 5) = 31$ $3+4(z+5)=31$ ?