How many grams is #5.72 * 10^21# atoms of #Li#?

1 Answer
Shubh
Apr 8, 2018

#2.067*10^46# gm

Explanation:

firstly, we have to calculate no. of moles
i.e. no. of moles = no. of atoms * #N_A(Avagadro's Number)#
no. of moles = #5.72*10^21*6.023*10^23#
no. of moles = #34.45*10^44=3.445*10^45#
mass of Li = molar mass * no. of moles
=#6*3.445*10^45=2.067*10^46# gm

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