Question

How do you find a standard form equation for the line with slope of a line passing through (-1,-4) and (7,-3)?

Answer 1

`y=(x/8)-3.875`

Explanation:

First find the slope using `m=(y^2 -y^1)/(x^2-x^1)`
`m= (-3+4)/(7-(-1))`
`m=1/8`

Now plug in one of the points into y=mx+b to solve for b
`-4=((-1)/8)+b`
`-4+(1/8)=b`
`b=-3.875`

Plug in your values and voila!
`y=(x/8)-3.875`