How do you solve $\frac{1}{2} (x - (75 - x)) = 5$ $1/2(x-(75-x))=5$ ?

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How do you solve $\frac{1}{2} (x - (75 - x)) = 5$ $1/2(x-(75-x))=5$ ?

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Answer 1 · 2018-04-12T04:56:07

x=84

Explanation:

$\frac{1}{2} (1 - (75 - x)) = 5$ $1/2(1-(75-x))=5$
$(\frac{1}{2} - \frac{1}{2} (75 - x)) = 5$ $(1/2-1/2(75-x))=5$
$(\frac{1}{2} - (\frac{75}{2} - \frac{x}{2})) = 5$ $(1/2-(75/2-x/2))=5$
$\frac{1}{2} - \frac{75}{2} + \frac{x}{2} = 5$ $1/2-75/2+x/2=5$
$\frac{x}{2} = 5 - \frac{1}{2} + \frac{75}{2}$ $x/2=5-1/2+75/2$
$\frac{x}{2} = 42$ $x/2=42$
$x = 42 \cdot 2$ $x=42*2$
$x = 84$ $x=84$

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How do you solve $\frac{1}{2} (x - (75 - x)) = 5$ $1/2(x-(75-x))=5$ ?

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