Question

How do you complete the equation `C_8H_18 -> C_6H_14 + __`?

Answer 1

`"C"_2"H"_4`

Explanation:

`"C"_8"H"_18 -> "C"_6"H"_14 + "__"`

There are `8` carbons & `18` Hydrogens in reactant side and `6` carbons & `14` Hydrogens in product side. So, another molecule should contain `2` carbons and `4` Hydrogens.

`"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)`
`color(white)(............................)"ethene"`

Answer 2

it is the example of Aromatization in which higher alkanes is divided into smaller akanes & alkenes.
so, eqn is,
`C_8H_18 rarr C_6H_14 + C_2H_4`
octane `rarr` hexane + ethene