How do you simplify $\sqrt{9 b^{3}} - \sqrt{16 b^{3}} + \sqrt{9 b^{3}}$ $sqrt(9b^3)-sqrt(16b^3)+sqrt(9b^3)$ ?

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Answer 1 · 2018-04-14T19:37:20

$3 \sqrt{b^{3}} - 4 \sqrt{b^{3}} + 3 \sqrt{b^{3}}$ $3sqrt(b^3) -4sqrt(b^3) +3sqrt(b^3)$
= $2 \sqrt{b^{3}}$ $2sqrt(b^3)$

Just get the square root of the number and leave b as it is.

How do you simplify sqrt(9b^3)-sqrt(16b^3)+sqrt(9b^3)√9b3−√16b3+√9b3sqrt(9b^3)-sqrt(16b^3)+sqrt(9b^3)?