How do you find the axis of symmetry, graph and find the maximum or minimum value of the function $f (x) = \frac{1}{3} {(x + 6)}^{2} + 5$ $f(x)=1/3(x+6)^2+5$ ?

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How do you find the axis of symmetry, graph and find the maximum or minimum value of the function $f (x) = \frac{1}{3} {(x + 6)}^{2} + 5$ $f(x)=1/3(x+6)^2+5$ ?

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Answer 1 · 2018-04-14T19:56:57

Expand the equation and simplify it and then complete the square.

Explanation:

$\frac{x^{3}}{3} + 4 x + 17$ $(x^3)/3 +4x+17$ This the equation you will get when you expand the bracket and simplify.

$\frac{1}{3} {(x + 6)}^{2} - 5$ $1/3(x+6)^2-5$ This is the equation when you complete the square. To find the X and Y value. Take what is in the bracket and equate it to zero. So, in this case, it is X+6=0 and X=-6.
Now for the Y value, the value which is in the far right is the Y value, in this case, it is -5. So the coordinates for the minimum value is (-6,-5)

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How do you find the axis of symmetry, graph and find the maximum or minimum value of the function $f (x) = \frac{1}{3} {(x + 6)}^{2} + 5$ $f(x)=1/3(x+6)^2+5$ ?

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How do you find the axis of symmetry, graph and find the maximum or minimum value of the function $f (x) = \frac{1}{3} {(x + 6)}^{2} + 5$ $f(x)=1/3(x+6)^2+5$ ?