How do you solve $3 (x - 5) - 4 (2 x - 4) = 2 (x - 11)$ $3(x-5)-4(2x-4)=2(x-11)$ ?

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Answer 1 · 2018-04-15T18:12:30

$x = \frac{23}{7}$ $x=23/7$

$3 (x - 5) - 4 (2 x - 4) = 2 (x - 11)$ $3(x-5)-4(2x-4)=2(x-11)$

$3 x - 15 - 8 x + 16 = 2 x - 22$ $3x-15-8x+16=2x-22$

$3 x - 8 x - 2 x = - 22 + 15 - 16$ $3x-8x-2x=-22+15-16$

$- 7 x = - 23$ $-7x=-23$

Multiply both sides by (-1) so the signs can change.

$7 x = 23$ $7x=23$

Now divide both sides by 7

$(cancel7x)/cancel7=23/7$

$x=23/7$

How do you solve 3(x-5)-4(2x-4)=2(x-11)3(x−5)−4(2x−4)=2(x−11) 3(x-5)-4(2x-4)=2(x-11)?