How do you solve x + 9 = 2(x - 1)^2? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Black Widow Apr 15, 2018 x_1=7/2 x_2=-1 Explanation: x+9=2(x^2-2x+1) x+9=2x^2-4x+2 -2x^2+x+4x+9-2=0 -2x^2+5x+7=0 //*(-1) 2x^2-5x-7=0 Now use the formula x_(1//2)=(-b+-sqrt(b^2-4ac))/(2a) a=2 b=-5 c=-7 x_(1//2)=(5+-sqrt((25-4*2(-7))))/(2*2) x_(1//2)=(5+-sqrt((25+56)))/4 x_(1//2)=(5+-sqrt(81))/4 x_(1//2)=(5+-9)/4 x_1=(5+9)/4=14/4=7/2 x_2=(5-9)/4=(-4)/4=-1 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1646 views around the world You can reuse this answer Creative Commons License