If a current of 3 A3A passing through a circuit generates 9 W9W of power, what is the resistance of the circuit?

1 Answer
Apr 16, 2018

1Omega

Explanation:

Given,
Power (p) = 9 W
Current (I) = 3 A
Resistance (R) = ?
We know that,
P = I^2 xx R
-> 9 = 3^2 xx R
-> 9 = 9 xx R
-> R = 9/9
:. R = 1 Omega
So, the resistance of the circuit is 1 Omega .