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How do you simplify the expression $(y^{9}) {(2 y^{2})}^{3}$ $(y^9)(2y^2)^3$ ?

2 Answers

Apr 20, 2018

$8 y^{15}$ $8y^15$

Explanation:

$(y^{9}) {(2 y^{2})}^{3}$ $(y^9)(2y^2)^3$

$= y^{9} \times 8 y^{6}$ $=y^9xx8y^6$

$= 8 y^{15}$ $=8y^15$

TIP) $x^{m} \times x^{n} = x^{m + n}$ $x^mxxx^n=x^(m+n)$
TIP) ${(x^{m})}^{n} = x^{m n}$ $(x^m)^n=x^(mn)$

Apr 20, 2018

The answer is $8 \cdot y^{15}$ $8*y^15$

Explanation:

$(y^{9}) . {(2 y^{2})}^{3} = {(y)}^{9} . {(2 y^{2})}^{3} = 8 \cdot {(y)}^{9} \cdot {(y)}^{6} = 8 \cdot y^{15}$ $(y^9).(2y^2)^3=(y)^9.(2y^2)^3=8*(y)^9*(y)^6=8*y^15$

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