How many moles are present in $"25 cm"^3$ of $"0.2 M"$ sodium hydroxide solution?

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Answer 1 · 2018-04-23T09:12:23

$5.0xx10^-3*mol$ with respect to $NaOH$ ....

By definition... $"concentration"="moles of solute"/"volume of solution"$

And thus $"moles of solute"="concentration"xx"volume of solution"$

And....

$0.20*mol*L^-1xx25*cm^3xx10^-3*L*cm^-3=5.0xx10^-3*mol$

What is $pH$ of this solution?

Answer 2 · 2018-04-23T09:14:08

$"0.005 moles"$

Base equation

$"concentration" = "moles"/("volume" ("in dm"^3)$

Here

Therefore

$0.2= x/0.025$

Multiply by $0.025$ on both sides to leave $x$ by itself

$- 0.2xx0.025=x$

$x = "0.005 moles" = 5xx 10^(-3) \ "moles"$

How many moles are present in "25 cm"^3"25 cm"^3 of "0.2 M""0.2 M" sodium hydroxide solution?