How do you solve $10x – 8 + 2x(3) = 4(x – 8)+ 9(3 – x)$ ?

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Answer 1 · 2018-04-25T15:04:51

Bring the constant and variables terms together :-

$10x – 8 + 2x(3) = 4(x – 8)+ 9(3 – x)$

$rArr 10x+6x-4x+9x=-32+27+8$

$rArr 21x=3$

$:.x=1/7$

How do you solve 10x – 8 + 2x(3) = 4(x – 8)+ 9(3 – x) 10x – 8 + 2x(3) = 4(x – 8)+ 9(3 – x)?