How many moles of NaOH are present in 18.5 ml of 0.130 M NaOH?

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How many moles of NaOH are present in 18.5 ml of 0.130 M NaOH?

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Answer 1 · 2018-04-28T18:36:08

We can solve this by the unitary method.

Explanation:

0.130 moles are present in 1000 mL (1L) of solution.

$w w w w w w$ $color(white)(wwwwww$ $1000 mL = 0.130 moles$ $"1000 mL = 0.130 moles"$
$w w w i w w w w w$ $color(white)(wwwiwwwww$ $1 mL = \frac{0.130}{1000} moles$ $"1 mL" = 0.130/1000 " moles"$
$w i w w w w w$ $color(white)(wiwwwww$ $18.5 mL = \frac{0.130}{1000} \times 18.5 moles$ $"18.5 mL" = 0.130/1000 xx 18.5" moles"$
$w w w w w w w w w w w$ $color(white)(wwwwwwwwwww$ $= 13 \times 18.5 \times 10^{- 5} moles$ $= 13 xx 18.5 xx 10^(-5) " moles"$
$w w w w w w w w w w w$ $color(white)(wwwwwwwwwww$ $= 2.41 \times 10^{- 3} moles$ $= 2.41 xx 10^(-3) " moles"$

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How many moles of NaOH are present in 18.5 ml of 0.130 M NaOH?

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