How do you solve #-4x > 12#?

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Answer 1 · 2018-04-30T04:38:00

#x<-3#

it is given

#-4x>12#

So

#=> 4x<-12 " "# [#div# by a negative #-># flip the sign]

#x< (-12)/4 => x<-3#

so the solution of this question is #x<-3#.

Answer 2 · 2018-04-30T15:54:33

#x<-3#

Given: #-4x>12#.

Divide by #4# on both sides.

#(-4x)/4>12/4#

#-x>3#

Switch signs. That means that the inequality sign flips as well.

#=>x<-3#