How do you solve $- 4 x > 12$ $-4x > 12$ ?

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Answer 1 · 2018-04-30T04:38:00

$x < - 3$ $x<-3$

it is given

$- 4 x > 12$ $-4x>12$

So

$\Rightarrow 4 x < - 12$ $=> 4x<-12 " "$ [ $\div$ $div$ by a negative $\to$ $->$ flip the sign]

$x < \frac{- 12}{4} \Rightarrow x < - 3$ $x< (-12)/4 => x<-3$

so the solution of this question is $x < - 3$ $x<-3$ .

Answer 2 · 2018-04-30T15:54:33

$x < - 3$ $x<-3$

Given: $- 4 x > 12$ $-4x>12$ .

Divide by $4$ $4$ on both sides.

$\frac{- 4 x}{4} > \frac{12}{4}$ $(-4x)/4>12/4$

$- x > 3$ $-x>3$

Switch signs. That means that the inequality sign flips as well.

$\Rightarrow x < - 3$ $=>x<-3$

How do you solve -4x > 12−4x>12-4x > 12?