How do you solve #7= 2- 3+ 4x#?

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Answer 1 · 2018-05-02T23:38:08

#x=2#

First, combine the like terms on the right side:

#7 = color(red)2 - color(red)(3) + 4x#

#2# minus #3# is #-1#.

#7 = -1 + 4x#

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Next, add #color(blue)1# to both sides to get rid of the #-1# on the right side.

#7 + color(blue)1 = -1 + 4x + color(blue)1#

#7 + color(blue)1 = cancel(-1) + 4x + cancelcolor(blue)1#

#8 = 4x#

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Finally, divide both sides by #color(orange)4# to get #x# on a side by itself.

#8/color(orange)4 = (4x)/color(orange)4#

#8/color(orange)4 = (cancel4x)/cancelcolor(orange)4#

#2 = x#

Final Answer