How do you find the value of $sin 630$ $sin 630$ ?

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How do you find the value of $sin 630$ $sin 630$ ?

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Answer 1 · 2018-05-04T04:54:04

$- 1$ $-1$

Explanation:

First, ${sin 630}^{\circ}$ $sin630^@$ means that it makes more than one cycle around the axes. That means that we can subtract one cycle, or $360^{\circ}$ $360^@$ , and the sine of that will still be the same.

So:
$630^{\circ} - 360^{\circ} = 270^{\circ}$ $630^@ - 360^@ = 270^@$

At $270^{\circ}$ $270^@$ , the coordinate is on the negative $y$ $y$ -axis, or at the coordinate $(0, - 1)$ $(0, -1)$ .

We know that the cosine of an angle is the $x$ $x$ -coordinate and the sine of an angle is the $y$ $y$ -coordinate. That means that ${sin 270}^{\circ} = - 1$ $sin270^@ = -1$ .

Hope this helps!

Answer 2 · 2018-05-04T04:54:17

$sin 630 = - 1$ $sin630 = -1$

Explanation:

630-360 = 270 degree

the coordinate of 270 degrees ( $3 \frac{π}{2}$ $3pi/2$ ) in the unit circle is (0,-1)
and sin is the y-value of the coordinate so sin630 is -1

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How do you find the value of $sin 630$ $sin 630$ ?

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