How do you add square root 3 + square root 12 - 4squareroot 75?

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How do you add square root 3 + square root 12 - 4squareroot 75?

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Answer 1 · 2018-05-05T06:23:12

$- 17 \sqrt{3}$ $-17sqrt(3)$

Explanation:

$\sqrt{3} + \sqrt{12} - 4 \cdot \sqrt{75}$ $sqrt(3)+sqrt(12)-4*sqrt(75)$

$= \sqrt{3} + \sqrt{3 \cdot 2^{2}} - 4 \cdot \sqrt{3 \cdot 5^{2}}$ $=sqrt(3)+sqrt(3*2^2)-4*sqrt(3*5^2)$

$= \sqrt{3} + 2 \sqrt{3} - 20 \cdot \sqrt{3}$ $=sqrt(3)+2sqrt(3)-20*sqrt(3)$

$= - 17 \cdot \sqrt{3}$ $=-17*sqrt(3)$

Answer 2 · 2018-05-05T06:23:47

The answer will be $- 17 \sqrt{3}$ $-17 sqrt 3$ , as shown by the calculation below.

Explanation:

$\sqrt{3} + \sqrt{12} - 4 \sqrt{75}$ $sqrt 3 + sqrt 12 - 4 sqrt 75$
= $\sqrt{3} + \sqrt{4 \cdot 3} - 4 \sqrt{25 \cdot 3}$ $sqrt 3 + sqrt (4*3) - 4 sqrt (25*3)$
= $\sqrt{3} + \sqrt{4} \sqrt{3} - 4 \sqrt{25} \sqrt{3}$ $sqrt 3 + sqrt 4 sqrt 3 - 4 sqrt 25 sqrt 3$
= $\sqrt{3} + 2 \sqrt{3} - 4 \cdot 5 \sqrt{3}$ $sqrt 3 + 2 sqrt 3 - 4*5 sqrt 3$
= $(1 + 2 - 20) \sqrt{3}$ $(1+2-20)sqrt 3$
= $- 17 \sqrt{3}$ $-17 sqrt 3$

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How do you add square root 3 + square root 12 - 4squareroot 75?

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