How do you multiply #(2x - 1) ( 4x ^ { 2} - 3x - 7)#? Algebra Properties of Real Numbers Multiplication of Rational Numbers 1 Answer Niya N. May 7, 2018 #(2x-1)(4x^2-3x-7)=8x^3-10x^2-11x+7# Explanation: Use distribution property: #(2x-1)(4x^2-3x-7)=2x(4x^2-3x-7)-1(4x^2-3x-7)# #=8x^3-6x^2-14x-4x^2+3x+7# #=8x^3-10x^2-11x+7# Answer link Related questions How do you multiply mixed rational numbers like a decimal and a fraction? How do you multiply rational numbers in fraction form? How do you multiply rational numbers? What is the multiplication identity property? What is the zero property of multiplication? How do you find the product of #2/3# and #1 1/2#? What are the rules of multiplying with positive and negative numbers? What is the product of #2.1 and -3.68#? How do you simplify #1/2*2/3*3/4#? What is the product of #3/5xx5/12#? See all questions in Multiplication of Rational Numbers Impact of this question 1719 views around the world You can reuse this answer Creative Commons License