What is the equation of a line that goes through $(- 6, 3)$ $(-6, 3)$ and has a slope of $- \frac{2}{3}$ $-2/3$ ?

Question

6417 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-11T00:47:25

$y = - \frac{2}{3} x - 1$ $y= -2/3x-1$

Use

$y = m x + b$ $y=mx+b$

Plug in the numbers

$3 = - \frac{2}{3} (- 6) + b$ $3=-2/3(-6)+b$

Solve

$3 = 4 + b$ $3=4+b$

Subtract $4$ $4$ from both sides

$- 1 = b$ $-1=b$

So

$y = - \frac{2}{3} x - 1$ $y=-2/3x-1$

What is the equation of a line that goes through (−6,3)(-6, 3) and has a slope of −23-2/3?