How do you solve $x^2 - 5x =0$ ?

Question

1757 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-14T18:33:39

Factorize $x$ as common
$x(x-5)=0$

Divide both sides by $x$
$x-5=0$ ( as $0/x=0$ )

Transfer the $5$
$x=5$
Voila!

Answer 2 · 2018-05-14T18:34:03

see below

We have, $x^2-5x=0$
$x(x-5)=0$
Thus,either $x$ can be $0$ or it can be $5$

How do you solve x^2 - 5x =0x^2 - 5x =0?