What is the perimeter and area of a right triangle with a hypotenuse of 26 and a leg of 24?

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Answer 1 · 2018-05-23T14:52:29

$"Perimeter" = 60$ and $"Area" = 120$

Assign the sides $b = 24 and c = 26$

Use the Pythagorean theorem,

$c^2 = a^2 + b^2$

,to find the length of side a:

$a = sqrt(26^2-24^2)$

$a = 10$

The perimeter is:

$"Perimeter" =a +b +c$

$"Perimeter" =10 +24 +26$

$"Perimeter" = 60$

The area is:

$"Area" = 1/2bh$

If we select side b as the base, then side a is the height:

$"Area" = 1/2(24)(10)$

$"Area" = 120$