How do you solve the system $4x=3y+31$ and $y=2x+7$ by substitution?

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Answer 1 · 2018-05-24T04:54:29

$(-26,-45)$

$4x= 3y+31$ -------(1)
$y=2x+7$ ----------(2)

Put (2) in (1),

$4x= 3(2x+7)+31$

$4x= 6x+21+31$

$4x= 6x+52$

$2x=-52$

$x= -26$

put in equation (2)

$y=2(-26)+7$

$y=-52+7$

$y=-45$

How do you solve the system 4x=3y+314x=3y+31 and y=2x+7y=2x+7 by substitution?