Question

How do you solve `3abs(2x-5)=39`?

Answer 1

x=-4 or x=9

Explanation:

lets find first where `2x-5=0` the answer to that is `x=2.5`
If `x >2.5` then `2x-5>0` so the ansolute value is `3(2x-5)=39`
If `x<2.5` then `2x-5<0` so the absolute value is `3(5-2x)=39`
So it gives u different solutions in the first case where the `x>2.5` is `6x-15=39=>6x=54=>x=9`
In the secont case where `x<2.5 its 15-6x=39=>6x=-24=>x=-4`

Answer 2

`x=9 or x=-4`

Explanation:

Well, we can divide the `3` out to get

`|2x−5|=13`

Now we know that `2x-5` must equal `13` or `-13` because it is the absolute value. We set `2x-5` equal to `13` and `-13` and solve for `x`.

So

`2x-5+5=13+5`

`2x=18`

Divide both sides by `2` and get

`x=9`

Also

`2x-5+5=-13+5`

`2x=-8`

Divide both sides by `2` and get

`x=-4`

There you have it. `x=9` or `x=-4`.