How do you multiply $x^{2} \cdot x^{8} \cdot x$ $x^ { 2} \cdot x ^ { 8} \cdot x$ ?

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How do you multiply $x^{2} \cdot x^{8} \cdot x$ $x^ { 2} \cdot x ^ { 8} \cdot x$ ?

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Answer 1 · 2018-05-25T01:53:57

Add the exponents $x^{2 + 8 + 1}$ $x ^ (2 +8 +1)$ = $x^{11}$ $x^11$

Explanation:

$x^{2} = x \times x$ $x^2 = x xx x$
$x^{8} = x \times x \times x \times x \times x \times x \times x \times x$ $x^8 = x xx x xx x xx x xx x xx x xx x xx x$
$x = x^{1} = 1 \times x$ $x = x^1 = 1 xx x$

Add all the x's ( 2 + 8 + 1)

By adding all the exponents to multiply

$x^{2 + 8 + 1} = x^{11}$ $x ^ (2 + 8 +1) = x^11$

Answer 2 · 2018-05-25T01:55:07

The answer is $x^{11}$ $x^11$ .

Explanation:

When one has the same number but with several different exponents, the multiplication of the values is the addition of the exponents. In this case, it would be

$2 + 8 + 1$ $2 + 8 + 1$

which would equal $11$ $11$ .

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How do you multiply $x^{2} \cdot x^{8} \cdot x$ $x^ { 2} \cdot x ^ { 8} \cdot x$ ?

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