Question

How do you multiply `x^ { 2} \cdot x ^ { 8} \cdot x`?

Answer 1

Add the exponents `x ^ (2 +8 +1)` = `x^11`

Explanation:

`x^2 = x xx x`
`x^8 = x xx x xx x xx x xx x xx x xx x xx x`
`x = x^1 = 1 xx x`

Add all the x's ( 2 + 8 + 1)

By adding all the exponents to multiply

`x ^ (2 + 8 +1) = x^11`

Answer 2

The answer is `x^11`.

Explanation:

When one has the same number but with several different exponents, the multiplication of the values is the addition of the exponents. In this case, it would be

`2 + 8 + 1`

which would equal `11`.