How do you simplify #7(x – 11)#?

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Answer 1 · 2018-05-26T14:07:43

#7x-77#

Use the distributive property:

#7(x-11)#

#7*x+7*-11#

#7x+(-77)#

#7x-77#

Answer 2 · 2018-05-26T14:07:58

#7x-77#

multiply each term, in the bracket, by the #7# outside the bracket

#7(x-11)=7xx x-7xx11#

#=7x-77#