What is the square root of a^2\b^5?

2 Answers
May 30, 2018

=(asqrtb)/(b^3)=abb3

Explanation:

I assume you meant:

=sqrt(a^2/b^5)=a2b5

=sqrt(a^2)/sqrt(b^5)=a2b5

=a/(b^2sqrt(b))=ab2b

now you need to rationalize the denominator by multiplying the expression by:

sqrtb/sqrtbbb

=a/(b^2sqrt(b))*sqrtb/sqrtb=ab2bbb

=(asqrtb)/(b^2*b)=abb2b

=(asqrtb)/(b^3)=abb3

May 30, 2018

(a sqrt b)/b^3abb3

Explanation:

sqrt(a^2/b^5)a2b5

:.=sqrt (a^2)/sqrt (b^5)

:.=(sqrt (a*a))/sqrt (b*b*b*b*b)

:.sqrt (a)*sqrt (a)=a

:.sqrt (b)*sqrt (b)=b

:.=a/(b^2 sqrt b) xx(b^2sqrtb)/(b^2sqrtb)

:.=(ab^2 sqrt b)/b^5

:.=(a sqrt b)/b^(5-2)

:.=(a sqrt b)/b^3