What is the equation of the line passing through $(3, 9)$ $(3,9)$ and $(10, 6)$ $(10,6)$ ?

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What is the equation of the line passing through $(3, 9)$ $(3,9)$ and $(10, 6)$ $(10,6)$ ?

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Answer 1 · 2018-05-30T23:00:27

$y = - x + 12$ $y=-x+12$

Explanation:

First, find the slope of the line using the equation $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$
$\frac{6 - 9}{6 - 3} =$ $(6-9)/(6-3)=$
$- \frac{3}{3} =$ $-3/3=$
$- 1$ $-1$
Now plug it into the slope-intercept formula $y = m x + b$ $y=mx+b$
$y = - x + b$ $y=-x+b$
To find the value of b, plug in the first coordinate pair for $x$ $x$ and $y$ $y$
$9 = - 3 + b$ $9=-3+b$
$b = 12$ $b=12$
The equation is $y = - x + 12$ $y=-x+12$

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What is the equation of the line passing through $(3, 9)$ $(3,9)$ and $(10, 6)$ $(10,6)$ ?

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