If the initial of an ideal gas at 2.250 atm is 62.00°c, what final temperature would cause the pressure to be reduced to 1.750 atm?

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Answer 1 · 2018-06-02T22:41:55

#"260.5 K"#

From Gay Lussac’s Law

#color(white)(...)"P ∝ T"#

#"P"_1/"T"_1 = "P"_2/"T"_2#

#"T"_2 = "P"_2 × "T"_1/"P"_1 #

#color(white)("T"_2) = 1.750 cancel"atm" × "(62.00 + 273) K"/(2.250 cancel"atm")#

#color(white)("T"_2) = 1.750 × "335 K"/2.250#

#color(white)("T"_2) = 260.5\ "K"#