How do you simplify $root5(32x^6)$ ?

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Answer 1 · 2018-06-05T18:41:54

$=2xroot5(x)$

$=root5(32x^6)$

$=root5(32x^5 *x)$

$=xroot5(32*x)$

$=xroot5(2*2*2*2*2*x)$

$=xroot5(2^5*x)$

$=2xroot5(x)$

Answer 2 · 2018-06-05T18:49:36

My thought

$root(5) (32*x^6)=root(5)32*root(5) (x^5*x)=2*x*root(5)x$

How do you simplify root5(32x^6)root5(32x^6)?