How do you solve $\frac{3}{5} - \frac{7}{2} x = \frac{3}{10}$ $3/5 - 7/2x = 3/10$ ?

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Answer 1 · 2018-06-06T02:42:00

$x = \frac{3}{35}$ $x = 3/35$

Given:

$\frac{3}{5} - 7 \frac{x}{2} = \frac{3}{10}$ $3/5 - 7x/2 = 3/10$

Make the denominators equal:

$\frac{3 \cdot 2}{5 \cdot 2} - \frac{7 x \cdot 5}{2 \cdot 5} = \frac{3}{10}$ $(3*2)/(5*2) - (7x*5)/(2*5) = 3/10$

Simplify:

$\frac{6}{10} - \frac{35 x}{10} = \frac{3}{10}$ $6/10 - (35x)/10 = 3/10$

Make $x$ $x$ positive:

$\frac{35 x}{10} = \frac{6}{10} - \frac{3}{10}$ $(35x)/10 = 6/10 - 3/10$

$\frac{35 x}{10} = \frac{3}{10}$ $(35x)/10 = 3/10$

Simplify both sides:

$\frac{35 x}{10} \cdot 10 = \frac{3}{10} \cdot 10$ $(35x)/10 * 10 = 3/10 *10$

Continue:

$35 x = 3$ $35x = 3$

Solve for x:

$\frac{35 x}{35} = \frac{3}{35}$ $(35x)/35 = 3/35$

Isolate the value:

$x = \frac{3}{35}$ $x = 3/35$

How do you solve 35−72x=3103/5 - 7/2x = 3/10?