How do you simplify $d^{3} \times d^{5}$ $d^3 xx d^5$ ?

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How do you simplify $d^{3} \times d^{5}$ $d^3 xx d^5$ ?

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Answer 1 · 2018-06-07T07:36:04

$d^{8}$ $d^8$

Explanation:

using the rules of exponents

$x^{m} \cdot x^{n} = x^{m + n}$ $x^m*x^n=x^(m+n)$

$d^{3} \cdot d^{5} = d^{3 + 5}$ $d^3*d^5=d^(3+5)$

$= d^{8}$ $=d^8$

Answer 2 · 2018-06-07T07:36:37

$d^{8}$ $d^8$

Explanation:

$d^3=underbrace(d xx d xxd )_"3 times"$

$d^5=underbrace(d xxd xxd xxd xxd)_"5 times"$

$d^3xxd^5=underbrace(d xxd xxd xxd xxd xxd xxd xxd)_("8 times")=d^8$

$"this may be generalised as"$

$•color(white)(x)d^3xxd^5=d^((3+5))=d^8$

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How do you simplify $d^{3} \times d^{5}$ $d^3 xx d^5$ ?

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