What are the extrema of f(x)=(x^2)/(x^2-3x)+8 on x in[4,9]?
1 Answer
Jun 10, 2018
The given function is always decreasing and therefore has neither maximum nor minimum
Explanation:
The derivative of the function is
and
The given function the function is always decreasing and therefore has neither maximum nor minimum
graph{x^2/(x^2-3x)+8 [-0.78, 17, 4.795, 13.685]}