How do you solve #(x - 13) ^ { 2} = 45#?

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Answer 1 · 2018-06-17T19:14:56

#x=+-sqrt(45) + 13#

We want to find the value of x, so we try to isolate.
we can take the square root of both sides which removes the squared from the brackets.

#sqrt((x-13)^2) = +-sqrt(45)#
#x-13 = +-sqrt(45)#

Then we just add 13 to both sides and we are left with

#x = +-sqrt(45) + 13#

Answer 2 · 2018-06-17T19:15:27

Take square root and rearrange to get the two answers

#(x-13)^2=45#

Take square root:
#x-13=+-sqrt(45)=+-3sqrt(5)#

#x=13+-3sqrt(5)#