Question

How do you divide `(2x^3+4x^2+2x+2)/(x^2+4x-2)`?

Answer 1

`(2x³+4x²+2x+2)/(x²+4x-2)=2x-4+(22x-6)/(x²+4x-2)`

Explanation:

`(2x³+4x²+2x+2)/(x²+4x-2)`
`=2(x³+2x²+x+1)/(x²+4x-2)`
`=2(x³+4x²-2x-2x²+3x+1)/(x²+4x-2)`
`=2x(cancel((x²+4x-2)/(x²+4x-2)))^(=1)+2(-2x²+3x+1)/(x²+4x-2)`
`=2x+2(-2x²-8x+4+11x-3)/(x²+4x-2)`
`=2x+4(cancel((-x²-4x+2)/(x²+4x-2)))^(=-1)+(22x-6)/(x²+4x-2)`
`=2x-4+(22x-6)/(x²+4x-2)`
\0/ here's our answer !