How do you solve $|(x/2) + 3| = 3x -3$ ?

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Answer 1 · 2018-06-27T17:25:25

$|(x/2)+3|=3x-3$
$x/2 + 3=+-(3x-3)$
Therefore, $x/2 + 3=(3x-3) or (3-3x)$
When, $x/2 + 3= 3x-3$
$6=(5x)/2$
$12=5x$
$x=12/5$
^1st answer

When, $x/2 +3=3-3x$
$(7x)/2=0$
$7x=0$
$x=0$

Therefore, $x=0 or x= 12/5$

How do you solve |(x/2) + 3| = 3x -3|(x/2) + 3| = 3x -3?