How do you simplify #\frac { 3x ^ { 3} y ^ { 2} } { 2x ^ { 2} y ^ { 3} }#?

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Answer 1 · 2018-07-04T11:45:27

Here.

Start by crossing out the #x# of the numerator with that of the denominator using indices rules.

#x^3/x^2 = x#

That's because the rule of indices states that when powers are divided, they get subtracted.

Do the same for the #y#.

You get:

#y^2/ y^3= 1/y#

Now since you can't simplify the 2 and the 3, you can leave them:

#(3x)/(2y)#

Answer 2 · 2018-07-04T13:48:43

#(3x)/(2y)# or I prefer it as #1.5xy^-1=(1.5x)/y#.

Given: #(3x^3y^2)/(2x^2y^3)#.

Separate into:

#=3/2*x^3/x^2*y^2/y^3#

#=1.5*x*1/y#

#=(1.5x)/y#

#=1.5xy^-1#