Question

How do find the vertex and axis of symmetry, and intercepts for a quadratic equation `y=2x^2 + 1`?

Answer 1

Vertex (0,1)
Axis of symmetry `x=0` or the y axis

Explanation:

x coordinate for axis of symmetry is found using `(-b)/(2a)`

`0/4=0` when `x=0, y=1`

It is a `uu` shaped parabola with the minimum at (0,1) so it does not cross the x axis