An electric toy car with a mass of $8 kg$ is powered by a motor with a voltage of $5 V$ and a current supply of $4 A$ . How long will it take for the toy car to accelerate from rest to $8/3 m/s$ ?

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Answer 1 · 2018-07-31T00:36:17

$a =0.9375 m/s^2$

I tried this:

$V= J/C$
$J= kgm^2/s^2$
$A=C/s$

$(5J/C*4C/s)/(8kg*8/3m/s)=$

$(20J/s)/(64/3kgm/s)=$

$(20kgm^2/s^2*1/s)/(64/3kgm/s)=$

$(20kgm^2/s^3)/(64/3kgm/s)=$

$(20kgm^2)/s^3*(3s)/(64kgm)= 0.9375 m/s^2$

An electric toy car with a mass of 8 kg8 kg is powered by a motor with a voltage of 5 V5 V and a current supply of 4 A4 A. How long will it take for the toy car to accelerate from rest to 8/3 m/s8/3 m/s?