What is the equation of the line between $(- 20, 2)$ $(-20,2)$ and $(- 3, 8)$ $(-3,8)$ ?

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Answer 1 · 2018-08-06T13:13:50

$6 x - 17 y + 154 = 0$ $6x-17y+154=0$

Equation of a line joining two points $(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$ is

$\frac{y - y_{1}}{y_{2} - y_{1}} = \frac{x - x_{1}}{x_{2} - x_{1}}$ $(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)$

Hence equation of line joining $(- 20, 2)$ $(-20,2)$ and $(- 3, 8)$ $(-3,8)$ is

$\frac{y - 2}{8 - 2} = \frac{x - (- 20)}{- 3 - (- 20)}$ $(y-2)/(8-2)=(x-(-20))/(-3-(-20))$

or $\frac{y - 2}{6} = \frac{x + 20}{17}$ $(y-2)/6=(x+20)/17$

or $17 y - 34 = 6 x + 120$ $17y-34=6x+120$

or $6 x - 17 y + 154 = 0$ $6x-17y+154=0$

What is the equation of the line between (−20,2)(-20,2) and (−3,8)(-3,8)?