How do you graph #y=(x-4)^2# by plotting points?

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Answer 1 · 2018-08-07T11:30:21

Assign a value to x to find the value of y.

If x is #-1#, #y=(-5)^2 = 25#

If x is zero #y=(-4)^2 = 16#

If x is 1, #y=(-3)^2 = 9#

If x is 4, #y=0#

etc.

You can plot it now:

graph{(x-4)^2 [-5.42, 14.58, -1.72, 8.28]}